Optimal. Leaf size=323 \[ -\frac {b x^4 \sqrt {c^2 x^2+1} \left (a+b \sinh ^{-1}(c x)\right )}{8 c \sqrt {c^2 d x^2+d}}+\frac {x^3 \sqrt {c^2 d x^2+d} \left (a+b \sinh ^{-1}(c x)\right )^2}{4 c^2 d}+\frac {\sqrt {c^2 x^2+1} \left (a+b \sinh ^{-1}(c x)\right )^3}{8 b c^5 \sqrt {c^2 d x^2+d}}-\frac {3 x \sqrt {c^2 d x^2+d} \left (a+b \sinh ^{-1}(c x)\right )^2}{8 c^4 d}+\frac {3 b x^2 \sqrt {c^2 x^2+1} \left (a+b \sinh ^{-1}(c x)\right )}{8 c^3 \sqrt {c^2 d x^2+d}}+\frac {b^2 x^3 \left (c^2 x^2+1\right )}{32 c^2 \sqrt {c^2 d x^2+d}}+\frac {15 b^2 \sqrt {c^2 x^2+1} \sinh ^{-1}(c x)}{64 c^5 \sqrt {c^2 d x^2+d}}-\frac {15 b^2 x \left (c^2 x^2+1\right )}{64 c^4 \sqrt {c^2 d x^2+d}} \]
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Rubi [A] time = 0.48, antiderivative size = 323, normalized size of antiderivative = 1.00, number of steps used = 11, number of rules used = 6, integrand size = 28, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.214, Rules used = {5758, 5677, 5675, 5661, 321, 215} \[ -\frac {b x^4 \sqrt {c^2 x^2+1} \left (a+b \sinh ^{-1}(c x)\right )}{8 c \sqrt {c^2 d x^2+d}}+\frac {x^3 \sqrt {c^2 d x^2+d} \left (a+b \sinh ^{-1}(c x)\right )^2}{4 c^2 d}+\frac {3 b x^2 \sqrt {c^2 x^2+1} \left (a+b \sinh ^{-1}(c x)\right )}{8 c^3 \sqrt {c^2 d x^2+d}}-\frac {3 x \sqrt {c^2 d x^2+d} \left (a+b \sinh ^{-1}(c x)\right )^2}{8 c^4 d}+\frac {\sqrt {c^2 x^2+1} \left (a+b \sinh ^{-1}(c x)\right )^3}{8 b c^5 \sqrt {c^2 d x^2+d}}+\frac {b^2 x^3 \left (c^2 x^2+1\right )}{32 c^2 \sqrt {c^2 d x^2+d}}-\frac {15 b^2 x \left (c^2 x^2+1\right )}{64 c^4 \sqrt {c^2 d x^2+d}}+\frac {15 b^2 \sqrt {c^2 x^2+1} \sinh ^{-1}(c x)}{64 c^5 \sqrt {c^2 d x^2+d}} \]
Antiderivative was successfully verified.
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Rule 215
Rule 321
Rule 5661
Rule 5675
Rule 5677
Rule 5758
Rubi steps
\begin {align*} \int \frac {x^4 \left (a+b \sinh ^{-1}(c x)\right )^2}{\sqrt {d+c^2 d x^2}} \, dx &=\frac {x^3 \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{4 c^2 d}-\frac {3 \int \frac {x^2 \left (a+b \sinh ^{-1}(c x)\right )^2}{\sqrt {d+c^2 d x^2}} \, dx}{4 c^2}-\frac {\left (b \sqrt {1+c^2 x^2}\right ) \int x^3 \left (a+b \sinh ^{-1}(c x)\right ) \, dx}{2 c \sqrt {d+c^2 d x^2}}\\ &=-\frac {b x^4 \sqrt {1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )}{8 c \sqrt {d+c^2 d x^2}}-\frac {3 x \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{8 c^4 d}+\frac {x^3 \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{4 c^2 d}+\frac {3 \int \frac {\left (a+b \sinh ^{-1}(c x)\right )^2}{\sqrt {d+c^2 d x^2}} \, dx}{8 c^4}+\frac {\left (b^2 \sqrt {1+c^2 x^2}\right ) \int \frac {x^4}{\sqrt {1+c^2 x^2}} \, dx}{8 \sqrt {d+c^2 d x^2}}+\frac {\left (3 b \sqrt {1+c^2 x^2}\right ) \int x \left (a+b \sinh ^{-1}(c x)\right ) \, dx}{4 c^3 \sqrt {d+c^2 d x^2}}\\ &=\frac {b^2 x^3 \left (1+c^2 x^2\right )}{32 c^2 \sqrt {d+c^2 d x^2}}+\frac {3 b x^2 \sqrt {1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )}{8 c^3 \sqrt {d+c^2 d x^2}}-\frac {b x^4 \sqrt {1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )}{8 c \sqrt {d+c^2 d x^2}}-\frac {3 x \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{8 c^4 d}+\frac {x^3 \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{4 c^2 d}+\frac {\left (3 \sqrt {1+c^2 x^2}\right ) \int \frac {\left (a+b \sinh ^{-1}(c x)\right )^2}{\sqrt {1+c^2 x^2}} \, dx}{8 c^4 \sqrt {d+c^2 d x^2}}-\frac {\left (3 b^2 \sqrt {1+c^2 x^2}\right ) \int \frac {x^2}{\sqrt {1+c^2 x^2}} \, dx}{32 c^2 \sqrt {d+c^2 d x^2}}-\frac {\left (3 b^2 \sqrt {1+c^2 x^2}\right ) \int \frac {x^2}{\sqrt {1+c^2 x^2}} \, dx}{8 c^2 \sqrt {d+c^2 d x^2}}\\ &=-\frac {15 b^2 x \left (1+c^2 x^2\right )}{64 c^4 \sqrt {d+c^2 d x^2}}+\frac {b^2 x^3 \left (1+c^2 x^2\right )}{32 c^2 \sqrt {d+c^2 d x^2}}+\frac {3 b x^2 \sqrt {1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )}{8 c^3 \sqrt {d+c^2 d x^2}}-\frac {b x^4 \sqrt {1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )}{8 c \sqrt {d+c^2 d x^2}}-\frac {3 x \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{8 c^4 d}+\frac {x^3 \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{4 c^2 d}+\frac {\sqrt {1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )^3}{8 b c^5 \sqrt {d+c^2 d x^2}}+\frac {\left (3 b^2 \sqrt {1+c^2 x^2}\right ) \int \frac {1}{\sqrt {1+c^2 x^2}} \, dx}{64 c^4 \sqrt {d+c^2 d x^2}}+\frac {\left (3 b^2 \sqrt {1+c^2 x^2}\right ) \int \frac {1}{\sqrt {1+c^2 x^2}} \, dx}{16 c^4 \sqrt {d+c^2 d x^2}}\\ &=-\frac {15 b^2 x \left (1+c^2 x^2\right )}{64 c^4 \sqrt {d+c^2 d x^2}}+\frac {b^2 x^3 \left (1+c^2 x^2\right )}{32 c^2 \sqrt {d+c^2 d x^2}}+\frac {15 b^2 \sqrt {1+c^2 x^2} \sinh ^{-1}(c x)}{64 c^5 \sqrt {d+c^2 d x^2}}+\frac {3 b x^2 \sqrt {1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )}{8 c^3 \sqrt {d+c^2 d x^2}}-\frac {b x^4 \sqrt {1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )}{8 c \sqrt {d+c^2 d x^2}}-\frac {3 x \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{8 c^4 d}+\frac {x^3 \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{4 c^2 d}+\frac {\sqrt {1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )^3}{8 b c^5 \sqrt {d+c^2 d x^2}}\\ \end {align*}
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Mathematica [A] time = 0.82, size = 268, normalized size = 0.83 \[ \frac {32 a^2 c \sqrt {d} x \left (c^2 x^2+1\right ) \left (2 c^2 x^2-3\right )+96 a^2 \sqrt {c^2 d x^2+d} \log \left (\sqrt {d} \sqrt {c^2 d x^2+d}+c d x\right )+4 a b \sqrt {d} \sqrt {c^2 x^2+1} \left (4 \sinh ^{-1}(c x) \left (6 \sinh ^{-1}(c x)-8 \sinh \left (2 \sinh ^{-1}(c x)\right )+\sinh \left (4 \sinh ^{-1}(c x)\right )\right )+16 \cosh \left (2 \sinh ^{-1}(c x)\right )-\cosh \left (4 \sinh ^{-1}(c x)\right )\right )+b^2 \sqrt {d} \sqrt {c^2 x^2+1} \left (32 \sinh ^{-1}(c x)^3+8 \left (\sinh \left (4 \sinh ^{-1}(c x)\right )-8 \sinh \left (2 \sinh ^{-1}(c x)\right )\right ) \sinh ^{-1}(c x)^2-32 \sinh \left (2 \sinh ^{-1}(c x)\right )+\sinh \left (4 \sinh ^{-1}(c x)\right )-4 \sinh ^{-1}(c x) \left (\cosh \left (4 \sinh ^{-1}(c x)\right )-16 \cosh \left (2 \sinh ^{-1}(c x)\right )\right )\right )}{256 c^5 \sqrt {d} \sqrt {c^2 d x^2+d}} \]
Antiderivative was successfully verified.
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fricas [F] time = 0.52, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {b^{2} x^{4} \operatorname {arsinh}\left (c x\right )^{2} + 2 \, a b x^{4} \operatorname {arsinh}\left (c x\right ) + a^{2} x^{4}}{\sqrt {c^{2} d x^{2} + d}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (b \operatorname {arsinh}\left (c x\right ) + a\right )}^{2} x^{4}}{\sqrt {c^{2} d x^{2} + d}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.54, size = 760, normalized size = 2.35 \[ \frac {a^{2} x^{3} \sqrt {c^{2} d \,x^{2}+d}}{4 c^{2} d}-\frac {3 a^{2} x \sqrt {c^{2} d \,x^{2}+d}}{8 c^{4} d}+\frac {3 a^{2} \ln \left (\frac {x \,c^{2} d}{\sqrt {c^{2} d}}+\sqrt {c^{2} d \,x^{2}+d}\right )}{8 c^{4} \sqrt {c^{2} d}}+\frac {b^{2} \sqrt {d \left (c^{2} x^{2}+1\right )}\, \arcsinh \left (c x \right )^{3}}{8 \sqrt {c^{2} x^{2}+1}\, c^{5} d}+\frac {b^{2} \sqrt {d \left (c^{2} x^{2}+1\right )}\, x^{5}}{32 d \left (c^{2} x^{2}+1\right )}-\frac {13 b^{2} \sqrt {d \left (c^{2} x^{2}+1\right )}\, x^{3}}{64 c^{2} d \left (c^{2} x^{2}+1\right )}-\frac {15 b^{2} \sqrt {d \left (c^{2} x^{2}+1\right )}\, x}{64 c^{4} d \left (c^{2} x^{2}+1\right )}-\frac {b^{2} \sqrt {d \left (c^{2} x^{2}+1\right )}\, \arcsinh \left (c x \right ) x^{4}}{8 c d \sqrt {c^{2} x^{2}+1}}+\frac {3 b^{2} \sqrt {d \left (c^{2} x^{2}+1\right )}\, \arcsinh \left (c x \right ) x^{2}}{8 c^{3} d \sqrt {c^{2} x^{2}+1}}+\frac {b^{2} \sqrt {d \left (c^{2} x^{2}+1\right )}\, \arcsinh \left (c x \right )^{2} x^{5}}{4 d \left (c^{2} x^{2}+1\right )}-\frac {b^{2} \sqrt {d \left (c^{2} x^{2}+1\right )}\, \arcsinh \left (c x \right )^{2} x^{3}}{8 c^{2} d \left (c^{2} x^{2}+1\right )}-\frac {3 b^{2} \sqrt {d \left (c^{2} x^{2}+1\right )}\, \arcsinh \left (c x \right )^{2} x}{8 c^{4} d \left (c^{2} x^{2}+1\right )}+\frac {15 b^{2} \sqrt {d \left (c^{2} x^{2}+1\right )}\, \arcsinh \left (c x \right )}{64 c^{5} d \sqrt {c^{2} x^{2}+1}}+\frac {3 a b \sqrt {d \left (c^{2} x^{2}+1\right )}\, \arcsinh \left (c x \right )^{2}}{8 \sqrt {c^{2} x^{2}+1}\, c^{5} d}+\frac {15 a b \sqrt {d \left (c^{2} x^{2}+1\right )}}{64 c^{5} d \sqrt {c^{2} x^{2}+1}}+\frac {a b \sqrt {d \left (c^{2} x^{2}+1\right )}\, \arcsinh \left (c x \right ) x^{5}}{2 d \left (c^{2} x^{2}+1\right )}-\frac {a b \sqrt {d \left (c^{2} x^{2}+1\right )}\, x^{4}}{8 c d \sqrt {c^{2} x^{2}+1}}-\frac {a b \sqrt {d \left (c^{2} x^{2}+1\right )}\, \arcsinh \left (c x \right ) x^{3}}{4 c^{2} d \left (c^{2} x^{2}+1\right )}+\frac {3 a b \sqrt {d \left (c^{2} x^{2}+1\right )}\, x^{2}}{8 c^{3} d \sqrt {c^{2} x^{2}+1}}-\frac {3 a b \sqrt {d \left (c^{2} x^{2}+1\right )}\, \arcsinh \left (c x \right ) x}{4 c^{4} d \left (c^{2} x^{2}+1\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: RuntimeError} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {x^4\,{\left (a+b\,\mathrm {asinh}\left (c\,x\right )\right )}^2}{\sqrt {d\,c^2\,x^2+d}} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {x^{4} \left (a + b \operatorname {asinh}{\left (c x \right )}\right )^{2}}{\sqrt {d \left (c^{2} x^{2} + 1\right )}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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